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3 3√3 one of the 3 is above the square root sign
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\[3\sqrt[3]{3}\]
\[9 \sqrt{3} \approx 15.59\]
no one of the threes is above the square root sign
My bad.. \[3\sqrt[3]{3} = \sqrt[3]{3*3^{3}} = \sqrt[3]{81} \approx 4.326\]
thanks
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