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cos^2-sin(2theta)= sin^2 theta
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\(\cos^2\theta-\sin2\theta=\sin^2\theta\)
Try:\[\cos^{2}(\theta)=1-\sin ^{2}(\theta)\] on \[\cos^{2}(\theta)\] and simplify.
Gudnyt.
hey but \[\sin ^{2}+\cos ^{2}=1 \] so like i get stuck where 1=2sinthetacostheta
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