Question

An object is thrown upwards with a speed of 14 m/s. How long does it take to reach its maximum height and return to a height of 5.0 m above the point from which it was thrown?

Answer 1

\[ y=v_{0y}t-\frac12gt^2 \]
Solve t for y =5, you'll end up with 2 value. Pick the greater t.

Answer 2

use eq.\[v=u+at\],at max. height,v=0,put a=-9.8,u=14