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OpenStudy (anonymous):
An object is thrown upwards with a speed of 14 m/s. How long does it take to reach its maximum height and return to a height of 5.0 m above the point from which it was thrown?
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OpenStudy (anonymous):
\[ y=v_{0y}t-\frac12gt^2 \] Solve t for y =5, you'll end up with 2 value. Pick the greater t.
OpenStudy (anonymous):
use eq.\[v=u+at\],at max. height,v=0,put a=-9.8,u=14
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