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What is the quadratic function that is created with roots -10 and -6 and a vertex at (-8, -8)?
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you can create a general setup, and then refine it using the roots and a scalar
huh?
\[f(x)=a(x-r_1)(x-r_2)\]
still lost ? sorry i am really new to this type of math
youll have to be more specific about what it is your not sure about. I am assuming by the nature of the question posted, that you have some basic knowledge about this stuff to work off of
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the values of the roots make the equation equal zero
2 roots means we need 2 setups. one for each root
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