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Mathematics 8 Online
OpenStudy (anonymous):

Find the derivative of the function (Use the chain rule).

OpenStudy (anonymous):

Would you be as kind as to provide the function in question?

OpenStudy (anonymous):

Sorry, internet screwed up as I was writing the function. \[y=\cos^2(2x)\]

OpenStudy (anonymous):

My attempt: f'(x)=2(cos(2x)) f'(x)=2(cos(2x))(-sin(2x)(2)

OpenStudy (anonymous):

You're correct man!

OpenStudy (anonymous):

Oh thats a relief, thanks! I guess I wrote the wrong answer in my notes.

OpenStudy (anonymous):

Is your solution in the book in this form f'(x)=-2sin(4x) ?

OpenStudy (anonymous):

I dont think so, I was just reviewing the examples we did in Calc today.

OpenStudy (anonymous):

Then you're correct. Go with that!

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