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Mathematics 13 Online
OpenStudy (anonymous):

lim as x ->0 5x-sin2x/x thank you!

OpenStudy (anonymous):

I think I should be multiplying both of them by 2 in order to cancel sin 2x out.. but that gives me 10x-2.. which is weird

OpenStudy (baldymcgee6):

http://gyazo.com/1250aa2264abf5d12365f66ef0b2fb28

OpenStudy (anonymous):

thank you!! .. but this wau seems really hard. is there another way??

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