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81.5 F= ___ c?
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27.5 degree celsius
\[T(°\text C)=\frac59\times(T(°\text F)-32)\] \[T(°\text F)=81.5 °\text F\] \[T(°\text C)=\frac59\times(81.6-32)=\qquad \dots\quad (°\text C)\]
\[F = \frac{ 9 }{ 5 }*C + 32\]
\[81.5 - 32 = \frac{ 9 }{ 5 }*C\]
\[49.5 *\frac{ 5 }{ 9 } = C\] \[27.5 = C\]
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27.5 degree C
lol, people are going crazy with medals on this question
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