Question

lim x-> 2 (x^3 - 8)/(2x - 4)

Answer 1

U need to FACTOR x^3-8

Answer 2

i already simplified the fraction as:

(x^3 - 8)/2(x - 2)

Answer 3

THATS GOOD @brygiger now, FACTOR x^3-8

Answer 4

is it (x-2)(x^2 + 2)^2?

Answer 5

*(x-2)(x^2 + 4)

Answer 6

NOPE:
a^3-b^3 =(a-b)(a^2 +ab +b^2)

Answer 7

DOES IT HELP?

Answer 8

yes thanks

Answer 9

so...
x^3 - 2^3 = (x-2) (x^2 + 2x + 4)

Answer 10

YES

Answer 11

NOW, u can cancel the terms (x-2)

Answer 12

doing it. but wait isn't
(a + b)^2 = (a^2 + 2(ab) + b^2) not (a^2 +ab +b^2)

Answer 13

x^3-8=x^3-2^3

Answer 14

answer is 6?

Answer 15

thanks :)

Answer 16

YEP