Question

#include #include #include float fact(int x); void main() { int n,x,m,a; float pmf,mean,var,p,q,ncr; printf("\t\t**********poisson Distribution***************\n"); scanf("%d",&x); printf("\nEnter value for alpha: "); scanf("%d",&a); pmf=(exp(-a)*pow(a,x))/fact(x); mean=a; var=a; printf("\n\nMean: %f\nVariancd: %f\npmf:%f",mean,var,pmf); getch(); } float fact(int f) { int i; float s=1.0; for(i=f;i>0;i--) { s=s*1; } return s; } help me friends its urgent i cant find satisfying output

Answer 1

hi thangeram,
what's the purpose of fact function ?

Answer 2

to check condition that ans must be below 1 and to calulate pmf

Answer 3

as I can see that function (fact) always returns a value of 1.0

Answer 4

hmm your correct but nick tell me why it is not giving satisfying output

Answer 5

I don't know what the "fact" function should do on its input f

Answer 6

i am showing you another example

Answer 7

#include <stdio.h>
#include <math.h> /* protype of "e", exp(x) == exp^x */
#include <conio.h> /* For clrscr() */


double Factorial1 (double a)
{
double answer = 1.0;
while(a>1)
answer *= a--;
return answer;
}

int main(void)
{
double result, res1, res2;
double i = 0.0, k = 0.00;
double answer = 0.0;

result = res1 = res2 = 0.0;

/* makes it easier to see input prompts */

printf("Enter mean: ");
scanf("%lf", &i);

printf("Enter value of interest: ");
scanf("%lf", &k);

/* factorial of value of interest */

answer = Factorial1(k);

/* formula for k */
result = pow(i,k);
res1 = 1/(exp(k));
res2 = (result * res1) / answer;

printf("answer is ... : %0.20lf", res2);

return 0;
}

Answer 8

may be it should evaluate the factorial value of f ? (f * f-1 * f-2 *...*1)

Answer 9

in that case you should have:

float fact(int f)
{
float s=1.0;
while(f>0)
{
s=s*f;
f--;
}
return s;
}

Answer 10

thanx nick

Answer 11

you're welcome :-)