A massless spring of force constant 19 N/m hangs vertically. a body of mass 0.20kg is attached to its free end and then released. assume that the spring was unstretched before the body was released. how far below the initial position the body descends.

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anonymous · Answer

Wow . thanks dude. But I'm rally curious, how did you come up with the kd=mg equation?

anonymous · Answer

Wait, a follow up question. Find the amplitude of the resulting motion, assumed to be simple harmonic.

anonymous · Answer

Oh, sorry. I thought it was in equilibrium. If it's released, then the problem is to find the mechanical energy before and after release.

anonymous · Answer

After the body has been attached, the spring should go down, right? and when it goes down, is that the equilibrium state of the system? or? I'm confused. How do i find the length increased when the body was attached?

anonymous · Answer

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