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Find the volume of a frustum of a pyramid with square base of side 12, square top of side 7 and height 12.
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you know this formula ?\[V _{F}=\frac{ 1 }{ 3 }h(A_{B}+A_{B^{'}}+\sqrt{A_{B}A_{B^{'}}})\]
Can you work it out for me?
Ab=12*12; Ab'=7*7 as well as h=12 Thus insert them in the formula
What did you get?
12*12 = 144 7*7 = 49
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?
insert the above numbers in their respective places of the formula and solve it you must get this finally 1108
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