HELP ? http://tinypic.com/view.php?pic=4re421&s=6
what are you thinking it is ....
im NOT sure. maybe perpendilur bisector?
how do you know that BDis perpendicular to AC?
idk.
it is not shown ... all we know is that BD bisects AC in half. that makes it a median ...but that is not one of the options
we can also rule out altitude .... because that also requires it to be perpendicular
so angle bisecor?
Right... BD cuts \(\angle ABC\) into two equal part
okay thanks
|dw:1348683434764:dw| Although it is not shown ... if a median is also an angle bisector in a triangle ... it HAS to also be the altitude AND the perpendicular bisector ... and the triangle must be either isosceles OR equilateral. so, technically speaking any option other than vertex is correct
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