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(a+6)+3bi=6-7i Find real numbers a and b such that the equation is true.
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just compare real and imaginary parts: so a+6=6 a=? 3b=-7 b=?
No helping me yet, I am really lost on this problem. Each one builds on the last so I am not seeing the results
which part did u not understand ?
Im supposed to solve for a and for b, but I struggle with imaginary parts and seeing the big picture.
imaginary terms are the terms with i so here we had 3bi=-7i --> 3b=-7 can u find b now ?
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a=0 and b=-2.33?
yup, u are correct :)
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