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Chain Rule Calculus f(x)=(2x-7)^3 I NEEED HELP!!
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3(2x-7)^2 * (2*1-0)
may i ask how you got that?
(f(x))^a = a(f(x))^(a-1) * f'(x)
f'(x) = 3(2x-7)^2 * d/(dx (2x-7) =3(2x-7)^2(2) =6(2x-7)^2
cant u jst simplify tis using formula for (a-b)^3=a^3+3ab^2-3a^2b-b^3 and then diff tis.. its much easier than to use product rule
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