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(g+4)-3g=1+g
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Open the brackets g+4-3g=1+g solve the like terms now -2g+4=1+g 4-1=g+2g ..........(By Transferring) 3=3g dividing 3 both sides \(\Large{\frac{3}{3}=\frac{3g}{3}}\) hence,g=1
2r-(5-r)=13+2r
and= 5g+4(-5+3g)=1-g
don't you wanna try @ashlynn ??
i have tried but i have four miniutes. i dont unerstand.
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2r-(5-r)=13+2r open the brackets first what do u gt tell me ??
i get 2r hold on plz
ok!
2r-5-r=13+2r which gives me... 1r -5=13+2r
so... r=-18?
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one mistake 2r-5+r=13+2r now what do u gt ?
13
no wait i meant 18
hey gtg. thanku
yw :)
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