Question

2sinx-3cosx/4sinx-9cos when cosecx = 13/12

Answer 1

cosecx=hyp/opp
\(144+{adj}^2=169\)
\({adj}^2=169-144\)
\({adj}^2=25\)
\(adj=5\)
\[sinx=\frac{opp}{hyp}\]
\[sinx=\frac{12}{13}\]
\[cosx=\frac{adj}{hyp}\]
\[cosx=\frac{5}{13}\]
\[\frac{2sinx-3cosx}{4sinx-9cos}\]
\[=\frac{2*\frac{12}{13}-3*\frac{5}{13}}{4*\frac{12}{13}-9*\frac{5}{13}}\]