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Chemistry
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potassium benzoate, C6H5CO2K, can be prepared from benzyl alcohol, C6H5CH2OH and KMnO4 in aqueous KOH. The manganese is converted to MnO2. balance the equation. I know that redox is used to solve this. can someone just get me started on what i need to do to set up the half reactions. i'm taking orgo and it's been a while... 3C6H5CH2OH+4KMnO4--->3C6H5CO2K+4H2O+KOH+4MNO2
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