Question

Factor completely: 3a^4y^3-12a^3y^2+6a^2y

A. 3(a^4y^3-4a^3y^2+2a^2)

B. 3a^2y(a^2y^2-4ay+2)

C. 3y(a^4y^2-4a^3y+2a^2))

D. Prime

Answer 1

3a^4 y^3-12a^3 y^2+6a^2 y
B. 3a^2y(a^2y^2-4ay+2)

Answer 2

You sure? Thanks! Can you explain it to me?

Answer 3

B

Answer 4

yeah, just factor out the 3a^2y and multiply them back again to(a^2y^2-4ay+2) for a recheck see if you get 3a^4 y^3-12a^3 y^2+6a^2 y

Answer 5

ok thnx SWAG n megan for the medal have fun