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If the two triangles are similar, solve for x A. x = 3 B. x = 6 C. x = 9 D. x = 12
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@AriPotta
@ajprincess
x + 6/ 6 = x + 9/7
\[\frac{x+6}{6}=\frac{x+9}{7}\] \(7(x+6)=6(x+9)\) \(7*x+7*6=6*x+6*9\) \(7x+42=6x+54\)
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can u solve for x @alainabbyboo22?
how do i solve for x ?
Follow the steps. 1.Subtract 6x both sides 2.Subtract 42 both sides
i'm still confused ): can you set it up for me ? like what do i subtract 6 by and what do i subtract 42 by ?
7x+42=6x+54 Subtract 6x both sides 7x+42-6x=6x+54-6x x+42=54 subtract 42 both sides x+42-42=54-42 x=12 Is it clear?
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yes ! now i see
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