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Mathematics 10 Online
OpenStudy (anonymous):

An architect drew a figure on a coordinate grid as shown to represent a scaled model of the front view of a garage. http://assets.openstudy.com/updates/attachments/506490efe4b0583d5cd3e670-renee99-1348769041002-46482588201182430am43442745.gif What is the length of the segment PQ of the roof rounded to the nearest hundredth? 6.71 units 7.00 units 8.49 units 9.00 units

OpenStudy (anonymous):

Okay, I got 5.19? Here's what I did: d=sqrt(6-0)^2+(3-6)^2 d=sqrt(6)^2+(-3)^2 d=sqrt(36+-9) d=sqrt(27) d=5.19?? What did I do wrong, can someone please explain this to me? Please?

OpenStudy (anonymous):

can anyone help? I really don't know what I did wrong?

OpenStudy (anonymous):

did I use the wrong formula?

OpenStudy (aripotta):

right formula, but you did it wrong. gimme a sec and i'll show you

OpenStudy (anonymous):

okay

OpenStudy (aripotta):

-3^2 = 9. you put -9. -3 x -3 = 9. when you multiply/divide two negative numbers, the answer is positive

OpenStudy (anonymous):

ohh okay, let me change it d=sqrt(36+9) d=sqrt(45) d=6.71!! :)

OpenStudy (aripotta):

yes!

OpenStudy (anonymous):

yay! thank you! :)

OpenStudy (aripotta):

no problem :)

OpenStudy (andriod09):

you did \[d=\sqrt{(6-0)^{2}+(3-6)^{2}}\] \[d=\sqrt{(6)^{2}+(-3)^{2}}\] \[d=\sqrt{(36+9)}\] \[d=\sqrt{(45)}\] \[d=6.71\]

OpenStudy (anonymous):

thanks for working it out!

OpenStudy (andriod09):

np!

OpenStudy (anonymous):

:D

OpenStudy (andriod09):

btw i typed all that out. i know how to work out the latix \[ \_]

OpenStudy (anonymous):

Yeah, it confused me, so I just typed it normally lol

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