Question

derivative of sqrtx lnx

Answer 1

\[u=\sqrt x\]\[v=\ln x\]\[(uv)'=u'v+v'u\]

Answer 2

how do i find v'? (ln x)'=?

Answer 3

you should really have that derivative memorized
http://tutorial.math.lamar.edu/pdf/Calculus_Cheat_Sheet_Derivatives_Reduced.pdf

Answer 4

if you care to prove that start with\[y=\ln x\iff x=e^y\]then differentiate implicitly with respect to x

Answer 5

Thank you!

Answer 6

welcome!