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12x^2-14x+4=0
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use the quadratic equation:\[x={-b \pm \sqrt{b^2-4ac}\over2a}\]
the equation \[12x^2-14x+4=0\]is in \[Ax+By+C=0\]format
use that to solve the quadratic equation and that should give you two values of x
other than that you could graph the equation using a graphing calculator and find the zeros which would give you the value of x
hope that's helpful @TeamJakeRosati_06 :)
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