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A C1 = 6.0 µF and a C2 = 3.0 µF capacitor are connected in series, and this combination is connected in parallel with a C3 = 3.5 µF capacitor (see Fig. 19-52). What is the net capacitance?
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Using the formulas for series and parallel capacitance. Your final equation should look like thi: \[(\frac{1}{6}+\frac {1}{3})^{-1}+3.5=?\]
5.5?
Yes
1/c = 1/c1 + 1/c2 + c3
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Thank you both :)
np :)
can i ask another question?
yep
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