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Mathematics 12 Online
OpenStudy (geometry_hater):

Determine whether each equation defines y as a function of x. X = Y^2

OpenStudy (anonymous):

In this case, no. You can rearrange it to be the case, but as given, "X is a function of y"

OpenStudy (geometry_hater):

Y= X ^2

OpenStudy (anonymous):

Well, no, that's not correct. But again, that's not what the question is actually asking.

OpenStudy (geometry_hater):

How exactly do you tell is Y is a function of x

OpenStudy (anonymous):

You don't need to do ANY of that.....

OpenStudy (anonymous):

Please look at the question.

OpenStudy (geometry_hater):

i would guess no because y isnt by itself..correct?

OpenStudy (anonymous):

It's not asking you to FIND y in terms of x, simply to say whether, as given, it is or not. In this case ...it is not. If "y" was "in terms of x" , y would be by itself y = something....

OpenStudy (anonymous):

my bad. I misunderstood

OpenStudy (anonymous):

...and within that "something", there would be an "x" in there.

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