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OpenStudy (anonymous):
calculate the integral x/[(x-a)(x-b)] when a does not equal b
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OpenStudy (arnavguddu):
use partial fraction to break this one into 2 fractions.....integrate each fractional part separately.... x/[(x-a)(x-b)] = A/(x-a) + B/(x-b).....first find A and B, by comparison method.... Then integrate A/(x-a) and B/(x-b).....
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