Question

limit as x -> pi/2 of tanx

Answer 1

\[\lim_{x \rightarrow \ {\pi }/ 2 }\tan(x)={\infty}\]

Answer 2

what happens when x -> pi/2

Answer 3

\[[\frac {sinx}{cosx} - \frac 1 {\cos(x)}] \]

\[ = \frac {sinx -1}{cosx.} \ Multiply \ \top \ and \ bottom \ by \ sinx \ + \ 1:\]= (sin^2 x - / [cosx ( sinx + 1)]

= - \[\frac {\cos^2 x} { [cosx ( sinx + 1)]} \frac { cosx}{ [ sinx + 1]} \ = \]

which approaches\[\frac {0}{2} = 0 \]

Answer 4

1/0
using lopitals rule
-cosx/sinx
0/1
answer is 0

Answer 5

as x tends to0 the equations tends to infinity

Answer 6

wow its actually undefined cos from the left its \[x \rightarrow \pi/2^- \rightarrow \infty\]
\[x \rightarrow \pi/2^+\rightarrow -\infty\]