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(4c2)3 simplify
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\[(4c^2)^3\] Is this what the problem looks like?
yes
\[4^2 \times (c^2)^2\] \[16c^4\]
When you apply an exponent to a group of factors like this, you apply it to each individual term. So it would look like this.\[(4c^2)^3=4^3(c^2)^3\] We cubes both terms, now we need to simplify the powers on the c. Make sense so far?
oh ya they are cubes answer would be 64c^6
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