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Mathematics 8 Online
OpenStudy (anonymous):

(4c2)3 simplify

zepdrix (zepdrix):

\[(4c^2)^3\] Is this what the problem looks like?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[4^2 \times (c^2)^2\] \[16c^4\]

zepdrix (zepdrix):

When you apply an exponent to a group of factors like this, you apply it to each individual term. So it would look like this.\[(4c^2)^3=4^3(c^2)^3\] We cubes both terms, now we need to simplify the powers on the c. Make sense so far?

OpenStudy (anonymous):

oh ya they are cubes answer would be 64c^6

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