Question

Determine the limit of the trig . function.
What should I do first ?

Answer 1

\[\lim_{x \rightarrow 0} \frac{ (\sin 2x) }{ \sin3x }\]

Answer 2

u know the lim x=> 0 sin x/x =1 ??

Answer 3

yes, what do i do with the 2x&3x ?

Answer 4

first divide numnerator and denominator by x, and tell me what u get..

Answer 5

(sin 2)/(sin3x)

Answer 6

lol no!
like this
\(\huge \frac{\frac{sin 2x}{x}}{\frac{sin3x}{x}}\)
got this?

Answer 7

so, \[\frac{ 2(\sin2x/2x) }{ 3(\sin3x/3x) }\]
then \[\frac{ 2(1) }{ 3(1) }\]?

Answer 8

absolutely !

Answer 9

thanks!

Answer 10

welcome ^_^