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Mathematics
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OpenStudy (anonymous):
in an examination,65% of total examineesif d total numbr offailures is 420 he total numbr of examinees is
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hartnn (hartnn):
65% passed means 100-65 = 35 % failed
did u get this?
OpenStudy (anonymous):
how do i solve it
OpenStudy (anonymous):
nut they want d numbr of student
OpenStudy (anonymous):
nut*
OpenStudy (anonymous):
but*
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OpenStudy (anonymous):
it wasnt nut it was but
hartnn (hartnn):
in an examination,65% of the total examinees passed if the numbr of failures is 420 the total numbr of examinees is????????????????????
hartnn (hartnn):
so 65% passed
how many % failed ?
OpenStudy (anonymous):
yea nd they hav given me options of
a)567 b)693 c)1200
OpenStudy (anonymous):
simply u know the % of failures and u want to know 100%
then required n of examinees is 100/(100-65) *420 =100/35 *420 =100 *12 =1200
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OpenStudy (anonymous):
i dint get it matricked
hartnn (hartnn):
lol @matricked i don't think @aldren understood the word of that
OpenStudy (anonymous):
they dnt want how much % but how many ppl
hartnn (hartnn):
to get how many ppl, we first need to know how much %
OpenStudy (anonymous):
yea exact;y
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hartnn (hartnn):
so how much % of ppl failed ?
OpenStudy (anonymous):
35%
OpenStudy (anonymous):
total is 100%
now passed is 65% then failed =100-65=35%
as per the question 35% is 420 hence 100% is 100/35 * 420 =1200
OpenStudy (anonymous):
thanx alot i understood
OpenStudy (anonymous):
can i ask another 1
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hartnn (hartnn):
new question, new post
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