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Mathematics 11 Online
OpenStudy (anonymous):

Prove that if a, b, and c are real numbers, then la+b+cl<=lal+lbl+lcl

OpenStudy (anonymous):

Can you do it with just two numbers, like |a+b| <= |a| + |b| ?

OpenStudy (anonymous):

Would it be basically the same proof?

OpenStudy (anonymous):

Exactly the same, yes.

OpenStudy (anonymous):

Can you prove it?

OpenStudy (anonymous):

Ok, yeah I have that one from an example in class.

OpenStudy (anonymous):

Well then it's the same thing. Think of it like |(a+b) + c| <= |(a+b)| + |c| <= |a| + |b| + |c|

OpenStudy (anonymous):

Oh, that is super easy then, thanks

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