Question

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Answer 1

For the first part
\[m=3\]
\[3=\frac{ y-0 }{ x-2 }\]
\[3(x-2)=y\]
\[3x-6=y\]
For the second part
\[m=\frac{-1}{3}\]
\[\frac{ -1 }{ 3 }=\frac{ y-(-4) }{ x-0 }\]
\[\frac{ -1 }{ 3 }=\frac{ y+4 }{ x }\]
\[\frac{-x}{3}=y+4\]
\[\frac{-x}{3}-4=y\]
So ur second part is right:)

Answer 2

yw:)