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Mathematics 15 Online
OpenStudy (anonymous):

PLEASE HELP !!!!!! Find P(x>1) X 1 2 3 4 P(x) 0.3 0.40 0.15 ?

OpenStudy (anonymous):

.20

OpenStudy (anonymous):

You just add up all P(x) where x > 1. There are 3 cases, P(x = 2 or x = 3 or x = 4). Since it must add up to 1, the faster way is just to subtract P(x = 1). So: 1 - 0.3 = 0.7

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