Question

domain and range of f(x)=sqrt(x^2-1)

Answer 1

Hint: \[ x^2 - 1 \]must be non-negative.

Answer 2

so would domain= (-infty, -1)cup(1, infty)
and range = [0, infty)

Answer 3

yes

Answer 4

oh except you can in fact take the square root of zero, so it would be
\[(-\infty, -1]\cup [1,\infty)\]

Answer 5

thanks!

Answer 6

Tip: Give the user to answer your question a medal. \Gives