Question

Two airplanes leave Dallas at the same time and fly in opposite directions. One airplane travels 80 mph faster than the other. After 3 hours, they are 2940 miles apart. What is the rate of each plane?

Answer 1

Let s = speed of slower airplane
Then speed of faster airplane = s + 80
Combined speed = s + s + 80 = 2s + 80 mph
Distance = speed * time
2940 = 3(2s + 80)
Can you now solve for s?

Answer 2

i figured it out before but thanks for the effort. While your here, for motion problems it distance divided by rate to find time right

Answer 3

Yes :)

Answer 4

thanks!

Answer 5

You're welcome :)