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OpenStudy (anonymous):
solve the equation. solution set is...z^23z=-2
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OpenStudy (anonymous):
z^2+3z=-2
OpenStudy (anonymous):
z^2+3z?
OpenStudy (anonymous):
I am not sure what to do next
OpenStudy (anonymous):
\[use this formula z={-b \pm \sqrt{b ^{2}-4ac}}/2a\]
OpenStudy (anonymous):
now here a= 1 b=3 and c=2
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