Question

How many times more intense is the sound of a space shuttle launch (180dB) than the sound of jet engine (140 dB)?

Answer 1

180/140=1.28 times

Answer 2

did you use this formula: L=10log(I/I0)?

Answer 3

i guess no

Answer 4

I'm suppose to..

Answer 5

but it's just ratio...of two quantities

Answer 6

sigh. Okay.

Answer 7

:)

Answer 8

140 = 10log(I/I0)
14=log(I/10)
\[\huge 10^{14} =10^{\log_{ } I/10}\]
\[\huge 10^{14} = I/10\]
\[\huge 10^{15} =I\]

Answer 9

find I for 180dB

divide by 10^15