Question

pls.......... answer the 28th question....

Answer 1

@ajprincess cn u help..??????

Answer 2

pls........

Answer 3

Let the remainder be r.
\(p(x)=x^3+8x^2+17x+ax\)
When p(x) is divided by (x+2) ,p(-2)=r
\(p(-2)=(-2)^3+8*(-2)^2+17(-2)+a(-2)\)
\(r=-8+32-34-2a\)
\(r=-10-2a-(1)\)
When p(x) is divided by (x+1), p(-1)=r
\(p(-1)=(-1)^3+8*(-1)^2+17(-1)+a(-1)\)
\(r=-1+8-17-a-\)
\(r=-10-a-(2)\)
Equate both equations and find a.

Answer 4

is a=0 .?????

Answer 5

@ajprincess

Answer 6

yup, u got it right, a=0