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Find the exact value of tan(arcsin(2/5)). For full credit, explain your reasoning.
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\[\arcsin(\frac{2}{5})=\theta\] is the same as \[\sin \theta=\frac{2}{5}\] so we draw a triangle sin is opposite over hypothenuse |dw:1348936495291:dw| solve for the missing side, then find \[\tan \theta\]
soo 2/sqrt(21) is the answer?
looks like it
alright thanks
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