Write the equation for the simple harmonic motion of a ball on a spring that starts at its lowest point of 6 inches below equilibrium, bounces to its maximum height of 6 inches above equilibrium, and returns to its lowest point in a total of 2 seconds.

Question

anonymous · Answer

@dpaInc

anonymous · Answer

@experimentX

experimentx · Answer

$$ m {d^2 x \over dt^2} = - kx, x(0) = x(2) -6, $$

experimentx · Answer

the time period is 2 ... the solution should be harmonic function.
so the answer should be 
$$ x(t) = -6 \cos \left( \pi t\right) $$

experimentx · Answer

http://www.wolframalpha.com/input/?i=Plot+-6+cos%28pi+t%29+from+0+to+4