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Mathematics 13 Online
OpenStudy (anonymous):

What is the real value solution set for |5x-3|<2 ?

jimthompson5910 (jim_thompson5910):

Hint: |5x-3|<2 expands out to -2 < 5x-3 < 2

OpenStudy (anonymous):

Ohh so then I add all sides by three?

jimthompson5910 (jim_thompson5910):

exactly

OpenStudy (anonymous):

I got it. Thanks.

jimthompson5910 (jim_thompson5910):

afterwards, you divide all sides by 5 to completely isolate x

OpenStudy (anonymous):

Yeah. Thanks.

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