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If the measure of angle T is (123-5x)º, what is the measure of its complement?
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(123-5x)º + compliment = 90º Solve for the compliment.
How do you do that?
You subtract (123-5x)º from both sides. Then you simplify.
Can u show me? please :)
I'll write \(c\) for compliment. \[(123-5x)º + c= 90º\] \[ c= 90º -(123-5x)º \] \[ c= (5x + 90- 123)º \] \[ c= (5x - 33)º \]
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Thanks!!! that makes sense now
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