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y = x + 4 –3x + 2y = 8 Type the first equation from the group you selected and identify the slope and the y-intercept of the equation. Describe how you would graph this line using the slope-intercept method. I really do need the help
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\[y-mx+b\]Where \(m\) is the slope and \(b\) is the value of y at the y-intercept.
I mean \(y=mx+b\)
x=0, y = 4
y = x + 4 –3x + 2(x + 4) = 8 -3x+2x+8=8 -x=0 x=0 y= x + 4 y=(0) + 4 y=4
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