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Simplify rational equation
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B is the answer
\[\LARGE\frac{ \frac{ 40a }{ b^2-5b+4 } }{ \frac{ 5a^2 }{ 2b-2 } }\] \[=\frac{ 40a* (2b-2)}{ (b^2-5b+4)*5a^2}\] Try factorising the numerator and denominator. Cancel if there are any common factors.
Can u do it @maxk?
not really
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@ajprincess good job
Thanx @mayankdevnani
so would b be the right answer
@ajprincess it's my pleasure
Can u factorise 2b-2?
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@maxk can u factorise it?
no im not really sure how to do that
Can u tell me vat is common to both 2b and 2?
the 2
What remains when u factor out 2?
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b
|dw:1349014423560:dw| Is it clear?
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