A tourist being chased by an angry bear is running in a straight line to-
ward his car at a speed of 4.0 m/s. The car is a distance d away. The bear
is 26 m behind the tourist and running at 6.0 m/s. The tourist reaches the
car safely. What is the maximum possible value for d?

I cannot wrap my head around this one :P
Thanks

Question

A tourist being chased by an angry bear is running in a straight line to-
ward his car at a speed of 4.0 m/s. The car is a distance d away. The bear
is 26 m behind the tourist and running at 6.0 m/s. The tourist reaches the
car safely. What is the maximum possible value for d?

I cannot wrap my head around this one :P 
Thanks

anonymous · Answer

if they both cover the same distance (which will then be the max safe distance)
6t -26m = d = 4t
so 2t =26m
t is 13
d= 4*13 = 52