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help me solve: (a^2)^-5
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\(\huge (x^n)^m=x^{mn}\) does this help?
so the answer is a^10?
2*(-5)=-10 so its a^(-10) ok?
so I don't flip the exponent and make it positive?
nopes, not here. you flip the sign of exponent only when you take its reciprocal \(\huge \frac{1}{x^n}=x^{-n}\)
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OHHHHH, okay- that helps. ty!
welcome ^_^
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