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OpenStudy (anonymous):
help me solve: (x^2m)^n
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hartnn (hartnn):
\(\huge (x^a)^b=x^{ab}\) same formula again
OpenStudy (anonymous):
Okay- so X^2mn?
hartnn (hartnn):
yes, if your question is \((x^{2m})^n\) then its correct but is your question \((x^2m)^n\) ??
OpenStudy (anonymous):
No, it's the first one
hartnn (hartnn):
then \(x^{2mn}\) is correct
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