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Mathematics 4 Online
OpenStudy (anonymous):

help me solve: (x^2m)^n

hartnn (hartnn):

\(\huge (x^a)^b=x^{ab}\) same formula again

OpenStudy (anonymous):

Okay- so X^2mn?

hartnn (hartnn):

yes, if your question is \((x^{2m})^n\) then its correct but is your question \((x^2m)^n\) ??

OpenStudy (anonymous):

No, it's the first one

hartnn (hartnn):

then \(x^{2mn}\) is correct

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