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Linear approximation :(
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\[\sqrt{99.8}\]
\[f(x)=\sqrt{x}\]
a=100
:) Correct
@hartnn hey can you check this out for me, i keep getting the wrong answer :(
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f'(a)=1/2sqrt(x)
yup, good so far
\[f(a)+f'(a)(x-a)\]
a=?
\[10+\frac{ 1 }{ 20 }(x-100)\]
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x is 99.8 only
because you are finding f(99.8) = f(x)
so 10+(99.8-100)/20 = ?
9.99
10.01
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close enough to answer 9.989 no, 9.99 was correct
10+(99.8-100)/20=9.99
oh ya
damn why do i keep messing x up!
with practice, you will be good at this :)
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thanks again @hartnn!
welcome again @Calle87 !
lets go to next question!
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