Question

The perimeter of a rectangle is 40 feet. The length of the rectangle is 2 feet more than 5 times the width. Find the dimensions of the rectangle.

Answer 1

Okay so remember the equation for perimeter?

Answer 2

no, what is it?

Answer 3

\(\large P_{rectangle}=2l+2w\)

Answer 4

So we know that \(40 = 2l+2w\) and that \(l = 5w+2\).

Answer 5

Do you know how to solve for \(l\) and \(w\) here?

Answer 6

Distribute 2 to 5w and 2 ?

Answer 7

Well, we substitute \(5w+2\) into the \(l\) of \(40=2l+2w\) to get \(40=2(5w+2) + 2w\)... Then we can distribute the two... yes.

Answer 8

I got w = 3

Answer 9

Is that the dimensions of the rectangle?

Answer 10

Well, now you have to solve for \(l\) by plugging in that \(3\). So we have \(l = 5(3)+2\)

Answer 11

thanks so much