Question

solve the following equations:

a. 2x^2-4x=6
b. 3^|x-1|=27

Answer 1

\[a) x^2-2x-3=0\\(x+1)(x-3)=0\\x=-1\text{ or }x=3\]

Answer 2

b. 3^3=27
so |x-1|=3, x-1=+/- (3)
x-1=3 > x=4
x-1=-3 > x=-2
so x=4 or x=-2