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OpenStudy (anonymous):
how do solve 5(x+4)=2(x+x+2)+42
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OpenStudy (anonymous):
Distribute the 5 and the 2, so 5(x+4)=2(x+x+2)+42 becomes 5x+20=2x+2x+4+42, simplify, so.... 5x+20=4x+46 then subtract one x from the other to isolate x.... x+20=46 then get x on one side so... x=26
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